ok i just solved this game:
question 8: B, you could have L on monday and tuesday, S on tuesday and wednesday, R on wednesday and thursday, and P on thursday and friday.
9: C, if L is on wednesday, then it also has to be on tuesday. so then you know you have P and R on both thursday and friday. this leaves S free to go in monday alone and also on tuesday.
10: A, if P is on wednesday, and you know that it cannot begin until the day after the last day for L, then you know that L has to be scheduled for monday and tuesday.
11: A, if P is alone on friday, then you know that P must also be on thursday. that means that R must be scheduled for wednesday and thursday. if R is on wednesday then L must be scheduled for monday and tuesday.
12: C, if L is alone on monday, then L must also be on tuesday. you can knock off A because R cannot go on tuesday ever. get rid of B because if R was alone on wednesday that means it also has to go on thursday, and there isnt enough room left for the S's and P's. C works because you could have L on monday and tuesday, S on wednesday and tuesday, and R and P on both thursday and friday.
if you need any more explanation let me know.