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Author Topic: October 1991 game #3 Logic Game. (Possible mistake. No Answer)  (Read 867 times)

Kantian

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October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« on: October 29, 2008, 03:32:49 AM »
I know this is a really old test but I'm running into some problems, which I cannot figure out this late evening.

ill change the names of cities and players but keep the game intact.

John spends 14days exactly, in 6 cities.
those 6 cities are in one of the countries of A, B, or C
Each country has many cities
John tours at least one city in each country
John spends at least 2 days in each city he tours
He spends no fraction of a day, only whole.

Question:

If John spends exactly 8 days in the cities of country A, what cannot be true?

answer = He tours exactly 2 cities in country A.

my question = but why can't he in country of A tour 2 cities of 2-6days or 3-5days or 4-4days? Rule only states he has to spend at least 2 days in each city.

Kantian

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Re: October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« Reply #1 on: October 29, 2008, 12:12:33 PM »
here's what i figured out. the only way for that answer to be wrong is if John had to visit all 6 cities. I don't see any rule stating that he must visit all 6 in spread of 14 days. It simply states he must visit at least 1 city in each country, meaning 3 cities in total and at least 2 days in each.

FutureLawyer9

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Re: October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« Reply #2 on: October 29, 2008, 12:41:47 PM »
here's what i figured out. the only way for that answer to be wrong is if John had to visit all 6 cities. I don't see any rule stating that he must visit all 6 in spread of 14 days. It simply states he must visit at least 1 city in each country, meaning 3 cities in total and at least 2 days in each.


What Test Number is Oct. 1991?

Kantian

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Re: October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« Reply #3 on: October 29, 2008, 01:42:32 PM »
here's what i figured out. the only way for that answer to be wrong is if John had to visit all 6 cities. I don't see any rule stating that he must visit all 6 in spread of 14 days. It simply states he must visit at least 1 city in each country, meaning 3 cities in total and at least 2 days in each.


What Test Number is Oct. 1991?

I think #2

theo

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Re: October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« Reply #4 on: October 29, 2008, 03:52:09 PM »
there is no mistake.

think harder, man!
quid leges sine moribus vanae proficiunt?

KaplanLSATInstructor

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Re: October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« Reply #5 on: October 29, 2008, 05:01:46 PM »
Read that first sentence again. It says that the person must spend 14 days in a total of six cities. Therefore, there has to be six cities.

If the person spent eight days in only two of the cities, that would leave six days in the remaining four cities. However, according to the rules, the person must spend at least two days in each city. The math can't work out, making (A) the correct answer.

(For those following along at home: this is the third game of PrepTest 2)


Kantian

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Re: October 1991 game #3 Logic Game. (Possible mistake. No Answer)
« Reply #6 on: October 30, 2008, 03:20:19 AM »
yeah I did this at 2AM and wasn't thinking coherently. Thanks everyone.