# Law School Discussion

## LSAT Preparation => Studying for the LSAT => Topic started by: jacy85 on May 24, 2004, 04:44:00 PM

Post by: jacy85 on May 24, 2004, 04:44:00 PM
I'm about to join the ranks of those who type out logic game questions for help.. :P  Sorry if this one's been asked already, but here goes..

Dec 1996, Game #3

An attorney is scheduling interviews with witnesses for a given week, Monday through Saturday.  Two full consecutive days of the week must be reserved for interviewing hostile witnesses.  In addition, nonhostile witnesses Q, R. U, X, Y, and Z will each be intervied exactly once for a full morning or afternoon.  The only witnesses who will be interviewed simultaneously with each other are Q and R.  The following conditions apply:

X must be interviewed on Thursday morning
Q must be intervied at some time before X
U must be interviewed at some time before R
Z must be intervied at some time after X and at some time after Y.

Here's what I got:

QR>X>Z

QR>U

Y>Z

AM   __  __  __  __  __  __

PM   __  __  __  X   __  __

M   T   W   T   F   S

And QR can't go on Saturday or Friday afternoon, since both U, X, and Z have to go after.

I'm finding all the questions really hard, and the QR thing and the block for hostile witnesses is screwing me up as well.  A little guidence would be a great help, even if it's just helping make the bigger inferences to point me in the right direction...

Post by: riceowl on May 24, 2004, 05:04:37 PM
I noticed two problems with your deductions.

First, you stated that QR is interviewed at some time before U (QR>U).  The third clue, however, states that U must be interviewed at some time prior to R - this should be stated as U>QR. Thus, QR CAN be interviewed on Friday afternoon (only X and Z need to come after QR).

Second, X is interviewed on Thursday morning (not Thursday afternoon). As a consequence, you can deduce that none of the hostile witnesses can be interviewed on Thursday.

I could probably be of more help if I knew the questions.

Hope this helps!